Primary 5 Maths: Triangle, Parallelogram and Trapezium Area — Practice Paper 4 (10 Questions)
Paper 4 is about joining and taking away: an L-shape is a rectangle minus a corner, two trapeziums turn into a parallelogram, and an overlap is subtracted once.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Primary 5 Maths: Areas of Triangles, Parallelograms and Trapeziums |
| Level | Primary 5 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 72 cm² | Base × height ÷ 2 = 16 × 9 ÷ 2. |
| 2 | 4 m² | No halving for a parallelogram: 2.5 × 1.6, keeping the decimal places. |
| 3 | 90 cm² | (11 + 19) × 6 ÷ 2; add the parallel sides first. |
| 4 | 16 cm | No halving here, so base = area ÷ height = 112 ÷ 7. |
| 5 | 156 cm² | The whole is 180 cm²; subtract the small 24 cm² rather than splitting into two parts. |
| 6 | 12 m | Reverse the formula: base = area × 2 ÷ height = 108 ÷ 9. |
| 7 | 30000 cm² | That is 3 m² first; 1 m² = 10,000 cm², so multiply by 10,000, not 100. |
| 8 | Base 12 cm, height 5 cm; each trapezium is 30 cm² | Turn one copy round and join the slant sides: the base is 4 + 8 = 12. The parallelogram is 60 cm², so one trapezium is half of it. |
| 9 | 72 cm² | Adding 48 and 48 counts the overlap twice, so subtract 24 once. |
| 10 | Area 81 cm², perimeter 36 cm | Area is 9 × 9; perimeter is four edges, 9 × 4. Different numbers and different units. |
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

