Primary 6 Maths: Applications of Percentages — Practice Paper 2
Paper 2 trains three moves: finding a percentage of an amount, finding the percentage increase or decrease between two numbers, and working back from a part to the whole. The settings are discounts, price rises and the weight of sugar.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 20 minutes |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: Primary 6 Maths: Applications of Percentages — Tutor Lesson Plan |
| Level | Primary 6 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 20 | 80 x 25/100 = 80 x 0.25 = 20. |
| 2 | 100 | Ten per cent of 250 is 25, so 40% is 25 x 4 = 100. |
| 3 | $96 | Twenty per cent off means paying 80%: 120 x 0.8 = 96. |
| 4 | 20% | 60 divided by 300 is 0.2, that is 20%. |
| 5 | 20% | The increase is 9, over the original 45: 9 divided by 45 is 20%. |
| 6 | 15% | The decrease is 12, and 12 divided by 80 is 0.15, that is 15%. |
| 7 | 240 | Work back to the whole: 84 divided by 0.35 gives 240. |
| 8 | $46 | The new price is 115% of the old: 40 x 1.15 = 46. |
| 9 | 60 g | 500 x 0.12 = 60 g. |
| 10 | The pupil subtracted 20 instead of 20% of 80, which is 16; the answer is 80 x 0.8 = 64 | A percentage must be taken of the original amount: 20% of 80 is 16, so the answer is 64. |
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

