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Secondary Biology: Inheritance and Mendel (Paper 2)

Secondary Biology: Inheritance and Mendel (Paper 2)

  • 2026-10-31

Secondary Biology: Inheritance and Mendel (Paper 2)

Ten original questions on 3:1 and 1:1 counts, using a test cross to tell TT from Tt, the 1:2:1 ratio under incomplete dominance and multiplying probabilities.

Direct answer Write the parental genotypes first. A test cross uses the recessive homozygote, and independent events multiply.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 25
Difficulty mix Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1
Chapter Chapter: Secondary Biology: Inheritance and Mendel
Level 4 basic, 3 advanced, 2 challenge and 1 redo question

02 Questions (10 items)

  1. FoundationTt is crossed with Tt and 800 seeds are sown. About how many are tall?
  2. FoundationTt is crossed with tt and 500 offspring are expected. How many are tall and how many short?
  3. FoundationWhat are the genotypes and phenotypes of the offspring of TT crossed with tt?
  4. FoundationHow many chromosomes does a human gamete carry?
  5. IntermediateA tall plant is test-crossed with a short one, giving 96 tall and 92 short offspring. What is the genotype of the tall parent?
  6. IntermediateWith incomplete dominance, RW is crossed with RW and 400 offspring are produced. What is the expected split?
  7. IntermediateA couple plans two children. What is the chance both are boys, and how many of 400 two-child families would that be?
  8. ChallengeHow can a test cross tell whether a tall plant is TT or Tt?
  9. ChallengeHow do genotype and phenotype differ, and why do they not always map one to one?
  10. Error redoA pupil claims a 3:1 ratio must appear in every experiment. Is that right?

03 Answers and one-line notes

# Answer One-line note
1 About 600 (200 short, a 3:1 ratio). The 3:1 ratio is expected, so multiply the total by three quarters.
2 250 of each, a 1:1 ratio. A cross with the recessive homozygote gives a 1:1 ratio.
3 All are Tt and all are tall. Each offspring receives one allele from each parent.
4 23, half the 46 found in body cells. Meiosis separates the pairs, so gametes are haploid.
5 Tt, because the near 1:1 ratio shows it can pass on a t allele. A TT parent would give only tall offspring in a test cross.
6 100 red, 200 pink and 100 white, a 1:2:1 ratio. With incomplete dominance the heterozygote shows an intermediate phenotype.
7 One in four (1/2 times 1/2), about 100 families. Each birth is independent, so the probabilities multiply.
8 Cross it with tt: all-tall offspring means TT, while a near 1:1 ratio means Tt. The tester parent must be the recessive homozygote.
9 Genotype is the allele combination (TT, Tt, tt); phenotype is the observable feature. TT and Tt look the same but differ in genotype. One phenotype can come from more than one genotype.
10 No. It is an expected ratio; small samples vary, so 20 seeds might give 14 to 6. The larger the sample, the closer the result comes to the expected ratio.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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