S4 ICT: Data and Networks – Practice Paper 4 (10 Questions)
- 2026-10-30
S4 ICT: Data and Networks – Practice Paper 4 (10 Questions)
Paper 4 works on capacity and bandwidth: binary and hexadecimal, a 24-bit colour image, the gap between Mbps and MB per second, a compression percentage and the size of an hour of video.
Quick answer Ten items, about twenty minutes. Items 01 to 04 cover binary, hexadecimal, card capacity and a colour image; items 05 to 07 cover decimal into binary, transfer time and Mbps into MB; items 08 and 09 cover compression and video size; item 10 redoes the KB conversion.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 20 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 ICT: Data and Networks – Tutor Lesson Plan |
| Level | S4 |
02 Questions (10 items)
- FoundationConvert the binary number 01101111 into decimal.
- FoundationWhat is the hexadecimal number A7 in decimal?
- FoundationHow many MB does an 8 GB card hold?
- FoundationA 1920 by 1080 pixel 24-bit colour image is stored uncompressed. How many MB is it?
- IntermediateWrite the decimal 300 as a binary number.
- IntermediateA 500 MB file crosses a 100 Mbps network. What is the shortest time in seconds?
- IntermediateA 45 Mbps broadband line delivers how many MB each second at most?
- ChallengeAn image of 6.22 MB compresses to 0.80 MB. What percentage is saved?
- ChallengeA one-hour video is recorded at a bitrate of 8 Mbps. About how many GB is the file?
- Error redoA student uses 1 KB = 1 000 bytes and says 5 KB is 5 000 bytes. What is the correct value?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 111 | Add 64, 32, 8, 4, 2 and 1 to get 111; the leading zero changes nothing. |
| 2 | 167 | A stands for 10, and 10 times 16 plus 7 gives 167. |
| 3 | 8,192 MB | Eight times 1 024 gives 8 192 MB, because GB to MB is a single step of 1 024. |
| 4 | 6,220,800 bytes, about 5.93 MB | 1920 times 1080 gives 2 073 600 pixels at three bytes each, so 6 220 800 bytes and about 5.93 MB. |
| 5 | 100101100 | 256 plus 32 plus 8 plus 4 makes 300, and the number needs nine bits in all. |
| 6 | 40 seconds | 500 MB is 4 000 Mbit, and dividing by 100 Mbps gives 40 seconds; a byte is eight bits. |
| 7 | 5.625 MB per second | Divide 45 by 8 to get 5.625, since one byte is eight bits. |
| 8 | about 87.1 per cent | Subtract 0.80 from 6.22 and divide by 6.22 to get about 87.1 per cent, leaving an eighth of the size. |
| 9 | 3,600 MB, about 3.52 GB | Eight Mbps over 3 600 seconds is 28 800 Mbit, that is 3 600 MB, and dividing by 1 024 gives about 3.52 GB. |
| 10 | 5,120 bytes | Memory steps by 1 024, so five times 1 024 gives 5 120 bytes; the 1 000 step is only for drive labels. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.


